Solve tan^2 theta + 1 = -2 tan theta on the interval 0° ≤ θ ≤ 360°.

Mathematics

1 answer:

IgorLugansk [536]3 years ago

4 0

Answer:

Step-by-step explanation:

$tan^2 \theta+1=-2 \tan \theta \\tan^2 \theta +2 tan \theta +1=0\\(tan \theta+1)^2=0\\tan \theta=-1=-tan 45=tan (360-45)=tan 315\\\theta =315 ^\circ$

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