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Mashcka [7]
3 years ago
8

I am trying to understand how to solve for X, then solve the equation

Mathematics
1 answer:
Alina [70]3 years ago
5 0

Answer:

x = 16

m<Y = 34°

Step-by-step explanation:

∆XYZ is an isosceles ∆. An isosceles ∆ has two equal sides, as well as the bases of the isosceles triangle are congruent. In this case, therefore:

<X = <Z

(6x - 23)° = (4x + 9)

Solve for x

6x - 23 = 4x + 9

Collect like terms

6x - 4x = 23 + 9

2x = 32

Divide both sides by 2

x = 16

m<Y = 180° - (m<X + m<Z) (sum of ∆)

m<Y = 180 - ((6x - 23) + (4x + 9))

Plug in the value of x

m<Y = 180 - ((6(16) - 23) + (4(16) + 9))

m<Y = 180 - (73 + 73)

m<Y = 34°

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2 years ago
What is the area of the figure below? Use 3.14 for pi. Round your answer to the nearest hundredth.
sammy [17]

Answer:

area of the figure ≈61.23 cm² to the nearest hundredth

Step-by-step explanation:

To find the area of the figure, we will follow the steps below;

Looking at the figure, we will see that the figure comprises of both semi-circle and a parallelogram

area of figure = area of semicircle + area of parallelogram

first, we will find the area of the semi-circle

area of a semi-circle = πr² /2

from the diagram given, diameter = 7cm

but diameter = 2r, this implies that radius r = d/2, hence radius r = 7/2 = 3.5 cm

π = 3.14

Lets insert the values into the formula

area of a semi-circle = πr² /2

                                    =3.14×3.5² /2

                                    =3.14×12.25 /2

                                     =19.2325 cm²

Area of a parallelogram = b×h

where b = base and h = height

from the figure given, base b = 7cm   and height h = 6 cm

Lets insert the values into the formula

Area of a parallelogram = b×h

                                       = 7×6

                                       =42 cm²

area of the figure = area of semicircle + area of parallelogram

                                =19.2325 cm²   +   42 cm²

                                =61.2325 cm²

                                ≈61.23 cm² to the nearest hundredth

area of the figure ≈61.23 cm² to the nearest hundredth

8 0
3 years ago
Are these(4,1) 1,-3) (2,0) solutions to this graph?
kogti [31]
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(1,-3) : yes because the line is not solid.
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7 0
3 years ago
Tanya is training a turtle for a race. For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile. At wh
vazorg [7]

Answer:

\frac{6}{20} \ mile\ per\ hour

Step-by-step explanation:

Given:

For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile

Question asked:

At what unit rate is the turtle crawling?

Solution:

As here<u> time taken is given</u> and the <u>distance traveled is also given </u>and hence we will apply speed and distance formula to find rate of crawling of turtle.

Time taken by turtle = \frac{1}{2} \ hour

Distance which can be traveled by turtle = \frac{3}{20} \ miles

Speed =\frac{Distance}{Time}

         =\frac{3}{20} \div\frac{1}{2} \\\\ =\frac{3}{20} \times\frac{2}{1} \\ \\ =\frac{6}{20}

Therefore, the rate at which the turtle is crawling is \frac{6}{20} \ mile\ per\ hour

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