What are the answer choices ?
<span>5 × 23 × 2 = 5 × 2 × 23 = 10 × 23 = 230</span>
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:

Step-by-step explanation:
7d – 4d – 3d – 5 = 6d
<em>(7d - 4d = 3d)</em>
3d - 3d -5 = 6d
<em>(3d - 3d = 0)</em>
0 - 5 = 6d
-5 = 6d
-5/6 = 6d/6
d = 
Hope this helps ^-^
The system of equations is
3d+7p=61.25
12d+9p=107.25