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ira [324]
3 years ago
11

The area of the square, the

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

As given in the question, we know that:

The ratio of the area of the circle to the area  of the square is π/4

  • The formula to find the volume of the cone is:

V = 1/3*the height*the base area

<=> V1 = 1/3*h*πr^{2}

  • The formula to find the volume of the pyramid is:

V2 = 1/3*the height*the base area

<=> V =  1/3*h*4r^{2}

=> the ratio of volume of the cone to the pyramid is:

= \frac{V1}{V2}

= (1/3*h*πr^{2} ) / ( 1/3*h*4r^{2} )

= π/4

S we can conclude that the volume of the cone equals π/4  the volume of the  pyramid

Hope it will find you well.

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Graph the functions f(x)=−6x+2 and g(x)=−2x+2+6 on the same coordinate plane.
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Answer:

here

Step-by-step explanation:

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4 years ago
-x + 3/2 = -y know how to do the Y equals MX plus b ​
MArishka [77]

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156

Step-by-step explanation:

6 0
3 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
Create an expression to the phrase "7 more than the product of 6 and the number n"
8090 [49]
6n+7, 13,19,25,31,37
4 0
4 years ago
No links pls
asambeis [7]

Answer:

Positive 1 over 6 raised to the 2nd power 1/62 or 1 over 36 which is 1/36. To find -6-2, take the inverse of -62.

(first find -62) -62 = -6 * -6 = 36

(then take the inverse of 36, which is 1 over 36) = 1 / 36 = 0.0277

so, -6-2 =0.0277

Step-by-step explanation:

3 0
3 years ago
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