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3 years ago

3^x+4=9^x-1 can you please help me thank you

Mathematics

1 answer:

Harrizon [31]3 years ago

4 0

Answer:

The answer is x = 0.93..

Step-by-step explanation:

- I converted 9^x to base 3

- Then I applied the exponent rule( a^b)^c = a ^bc

- After that I applied the other exponent rule a^bc = ( a^b) ^c

- I then rewrited the equation and solved it

- And I got x= 0.93..

Please BRAINLIEST!

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Given the pattern rule Tn=n2-1<br><br> what are the first 3 terms of the pattern

sergeinik [125]

Answer:

0, 3 , 8

Step-by-step explanation:

substitute n = 1, 2, 3 into the pattern rule

T₁ = 1² - 1 = 1 - 1 = 0

T₂ = 2² - 1 = 4 - 1 = 3

T₃ = 3² - 1 = 9 - 1 = 8

8 0

2 years ago

Solve for n please, with work , thank you!

Paul [167]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )$

Solve the inequality algebraically.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )$

Use the distributive property to multiply -4 by 2n-8.

$\sf1-3n>-1-8n+32$

Add -1 and 32 to get 31.

$\sf1-3n>31-8n$

Add 8n to both sides.

$\sf1-3n+8n>31$

Combine -3n and 8n to get 5n.

$\sf1+5n>31$

Subtract 1 from both sides.

$\sf5n>31-1$

Subtract 1 from 31 to get 30.

$\sf5n>30$

Divide both sides by 5. As 5 > 0, the direction of the inequality remains the same.

$\sf \: n>\frac{30}{5} \\$

Divide 30 by 5 to get 6.

$\boxed{ \boxed{ \bf \: n>6 }}$

3 0

3 years ago

Read 2 more answers

Ed has 93 marbles. In which sequence can he arrange them and use all the marbles?

Kaylis [27]

A.) asequence<span> with six terms that starts with 1

</span>

4 0

4 years ago

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

$P(B) = \frac{8}{12}$

$P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}$

<h3><u>Find </u><u> P(R | B)</u></h3><h3> $P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}$ </h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

$\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%$

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0

4 years ago

Jonah has read 265 pages. He has 147 more to read. How many pages did he read in all.

-BARSIC- [3]

Answer:

the pages read =265 more pages=147hedidnotread so pages he read =265

7 0

3 years ago