Square root of 72x^2 z^3

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

<u>Taking power $\dfrac{1}{6}$ both side</u>

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

Volume and surface area are often compared by manufacturers in order to maximize how much of something can go inside of a packag

notka56 [123]

We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.

Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.

Find the Volume
Volume

l = 27 cm
w = 14 cm
h = 22 cm

V = 27 *14 * 22
V = 8316 cm^3

Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558

Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.

$\frac{SA}{V} = \frac{2*L*W + 2*L*H + 2*W*H}{L*W*H}$

Another way to do this is to consider a cube which might give you a more useful result.

s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2

$\frac{SA_cube}{V_cube} = \frac{6s*s}{s*s*s}$
$\frac{SA}{V} = \frac{6}{s}$

That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.

4 0

3 years ago

Pleeeeeeessssssseeee help

lozanna [386]

Answer:

0.25, 5/8, 11/16

Step-by-step explanation:

1st, make all of them to decimal or fraction (recommended). I will do decimal this time because it's easier. 11/16 = 0.6875; 5/8 = 0.625 . So we can easily get which one is bigger or smaller.

5 0

3 years ago

Read 2 more answers

please help 100 points!!! will give crown to best answer if f(x) = 3x^2 -2x + 4 and g (x) = 5x ^2 + 6x -8 find (f-g) (x)

Alexxandr [17]

(f-g)(x) will be 3x^2 -2x+4 -(5x^2+6×-8)
distribute the -sign, gives us
3x^2-2x+4-5x^2-6x+8,
now combine like terms and should get,
-2x^2-8x+12,
final answer,
(f-g)(x)= -2x^2-8x+1×,
hope it helped,
good luck

8 0

3 years ago

Read 2 more answers

Find all of the points on the y-axis that are twice as far from (-6,0) as they are from (sqrt3,0)

mario62 [17]

I honesty dont know LOL

6 0

3 years ago