Answer:
Last one
Step-by-step explanation:
I’ve attached my work, hope this helps!
If the original population has a Normal distribution, then the distribution of the sample mean is also Normal.
If we extract random samples of size n from a population with half a μ and standard deviation σ, then the distribution of the sample mean will have the following parameters:
μ_Xbar = μ
σ_Xbar = σ/ √(n).
Where:
μ = 50
σ = 4
n = 20
So:
μ_Xbar = 50
σ_Xbar = 0.8944
Answer:
about 0.0143 microfarads
Step-by-step explanation:
The effective capacitance of capacitors in series is the reciprocal of the sum of their reciprocals:
1/(1/0.02 +1/0.05) = 1/(50+20) = 1/70 ≈ 0.0143 . . . microfarads
