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borishaifa [10]
4 years ago
12

What is the nth term in the sequence: 15, 22, 31, 42, 55

Mathematics
1 answer:
Lynna [10]4 years ago
5 0
Counting by seven’s then 9 then 10 then 13
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The volume of a cubic box is 10 to the power of 6 cubic millimeters. Write the volume in standard form
Vinil7 [7]
1 \times 10^{6} mm^{3}
5 0
3 years ago
PLZZZ HELP ON THIS I"M TRYING MY BEST BUT I NEED HELP PLZZZZZZZ HELP ME IT IS 50 POINTS!!!!
Yakvenalex [24]

Answer:

1. 142. 2. adjacent angles.

Step-by-step explanation:

1. because it is less then 180, that would be flat, and it is bigger then 132.

2. because they are adjacent to each other.

7 0
3 years ago
Penelope buys bracelets in bulk at a cost of $8 each to sell at her store. She uses a markup rate of 125%, which is added to the
slega [8]

Answer:

$18.00

Step-by-step explanation:

8 x 1.25 = 10

8 + 10 = 18

5 0
3 years ago
Pythagoras help needed please
boyakko [2]

Answer:

See explanation

Step-by-step explanation:

Find the diagonal of the square. The side of the square is 5 cm long. By the Pythagorean theorem,

\text{Diagonal}^2=\text{Side}^2+\text{Side}^2\\ \\\text{Diagonal}^2=5^2+5^2\\ \\\text{Diagonal}^2=25+25\\ \\\text{Diagonal}^2=50\\ \\\text{Diagonal}=\sqrt{50}=5\sqrt{2}\approx 7.07\ cm

If the square (being inside the circle) touches the circle, then the diagonal of the square is exactly the diameter of the circle. The diameter of the circle is twice the radius of the circle, so

\text{Diameter}=2\times 5=10\ cm

Since the diagonal is shorter than the diameter, the square can fit into the circle without touching the circle.

6 0
4 years ago
A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What
Jet001 [13]

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

  • Number of faces 4.
  • Number of vertices of a triangular pyramid is 6.
  • The volume  is \frac13 AH. A= area of the pyramid's base and H= height of the pyramid.
  • The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is \frac12 \times base \times height.

The lateral surface area of the triangular pyramid is

=3(\frac12 \times base \times height)

=3(\frac12\times 10\times8.6) cm squared

=129 cm squared

The total surface area of triangular pyramid is

=Area of the base + lateral surface area

=(43+129) cm squared

=172  cm squared

8 0
4 years ago
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