Answer:
(a) 0.5948
(b ) 0.0392; A. Yes , because the probability is less than 0.05
(c) 0.3660
Step-by-step explanation:
Probability of regular soda; P (regular soda) = 4/18
Probability of diet soda; P (diet soda) = 14/18
Let R = Outcome of Regular soda
D = Outcome of Diet soda
P (R) = 4/18
P(D) = 14/18
Note that it is a probability without replacement situation
The total sample space for randomly selecting two cans from the 18 packs is given as :
R R
R D
D R
D D
(a.) Determine the probability that both contain diet soda.
P(both Diet Soda) = P (DD)
= 14/18 x 13/17
= 0.59477
≈ 0.5948
(b.) Determine the probability that both contain regular soda.
P (both regular soda) = P (R R)
= 4/18 x 3/17
= 0.039215
≈ 0.0392
Would this be unusual?
A. Yes , because the probability is less than 0.05
(c.) Determine the probability that exactly one is diet and exactly one is regular
P(exactly one regular) = P(RD) + P(DR)
= (4/18 x 14/17) + (14/18 x4/17)
= 0.36601
≈ 0.3660
