Given that the hyperbola has a center at (0,0), and its vertices and foci are on y-axis. This, the equation of the hyperbola is of the form
x²/a²-y²/b²=-1 (a>0, b>0)
In the equation, vertices are (0, +/-b) .
Thus,
b=60
Foci (0,+/-√(a²+b²))
thus
√(a²+60²)=65
hence solving for a²
a²=65²-60²
a²=625
a²=25²
hence the equation is:
x²/25²-y²/60²=-1
Answer:
143π in³
Step-by-step explanation:
A basketball has the shape of a sphere
Volume of a basketball = 4/3πr³
Diameter = 9.5 in
Radius = diameter/2
= 9.5/2
= 4.75 in
Volume of a basketball = 4/3πr³
= 4/3 * π * 4.75³
= 4/3 * π * 107.17
= (4*π*107.17) / 3
= 428.68π / 3
= 142.89π in³
Approximately
143π in³ to the nearest whole number
Answer:
x-6 <1
Step-by-step explanation:
Answer: 0.75
Step-by-step explanation:
-4.125/-5.5 = 3/4 or 0.75
-4.125/0.75 = -5.5
