The four-chambered heart of a humpback whale weighs approximately 430 pounds. 1 kilogram is equal to 2.2 pounds. What is the wei
1 answer:
Answer:
B. 195.5 kg
Step-by-step explanation:
Given
Weight in pounds = 430 pounds
1 kilogram = 2.2 pounds
Required
The weight in kilogram
Let x represents the weight of the humpback's whale's heart in kilogram
Such that;
By Cross multiplication
Divide both sides by 2.2lb
Approximate
Hence, the weight of the heart is 195.5kg
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Answer:
Step-by-step explanation:
Both equations should be in slop-intercept form (y=mx+b)
So add -2x to -6. Your equation should look like this
y=2x-6
In y=mx+b
b will fall on y-axis
mx is rise/run
So in the first equation plot -6 on y axis and go up 2 and over 1(because 2x is equivalent to 2/1 x)
In the second equation plot -1 on the y axis. Then go up 1 and over 3 from that point.
If AM=BM, then point M is a middle point of side AB.
1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that
2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.
3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.
4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.
5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,
6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then
m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.
Answer: m∠A=120°, m∠B=m∠C=30°.