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guapka [62]
3 years ago
7

Whats the greatest common factor of 20 and 40

Mathematics
2 answers:
ollegr [7]3 years ago
5 0
Greatest common factor is 20
katen-ka-za [31]3 years ago
3 0

Factors of 20 - 1 2 4 5 10,20

Factors of 40 -1, 2, 4, 5, 8, 10, 20

Then the greatest common factor is 20.

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I need help with this problem what fractions are equivalent to 4.05 repeating
kow [346]

Answer:

401/99 and 802/198

Step-by-step explanation:

Unfortunately the other answer to this question is wrong - you are looking for something equivalent to 4.0505050505050505, not just 4.05.

Typing the answer suggestions into a calculator you get:

405/99 = 4.0909090909 which is incorrect

401/99 = 4.0505050505 which is correct

81/33 = 2.45454545455 which is incorrect

802/198 = 4.0505050505 which is correct

405/100 = 4.05 which is incorrect as it doesn't repeat.

Hopefully this helps, let me know if you have any questions :)

6 0
2 years ago
Write an algebric pharse for five times a number increased by nine.<br><br> i need help
trasher [3.6K]

Answer:

Step-by-step explanation:

five times a number increased by nine is

5x+9

x is the unknown number being multiplied by 5

increase= add

so add by 9

6 0
3 years ago
Subtract (x² + 5x – 6) – (3x^2 – 7x + 1).<br> What is the difference?
Lorico [155]
1. Distribute the Negative Signs
2. Combine like terms
-2x^2 + 12x-7
4 0
3 years ago
Algebra:please answer #1 and show work
Novay_Z [31]
So 12 mins to 600 feet
35 mins=1900 feet
find the slope which is change in top over change in bottom (aka slope) so to find do
(y1-y2)/(x1-x2)
we want, per minute, so put the time as x1 and x2
x1=12
y1=600
x2=35
y2=1900
subsitutte
(600-1900)/(12-35)=-1300/-23=56.5 per minute
the answe ris 56.5 feet per minute or the last answer
4 0
2 years ago
$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent
photoshop1234 [79]

\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\&#10;\\&#10;\text{we know that the amount after t year when compounded is given by}\\&#10;\\&#10;A=P\left ( 1+\frac{r}{n} \right )^{nt}\\&#10;\\&#10;\text{here P is the principal amoount, so }P=7000,\\&#10;\\&#10;\text{r is the interest rate, }r=11\%=0.11\\&#10;\\&#10;\text{n is the number of times in a year, here semiannulay, so }n=2,\\&#10;\\&#10;\text{and t is the time, so }t=21\\&#10;\\&#10;\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\&#10;\\&#10;\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\&#10;\\&#10;\Rightarrow A=7000\left ( 1.055 \right )^{42}\\&#10;\\&#10;\Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

7 0
3 years ago
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