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VLD [36.1K]
4 years ago
8

Is 5/ 8 less or more than 1 mile

Mathematics
1 answer:
wel4 years ago
3 0

Answer:

5/8 of what

Step-by-step explanation:

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If YWZ=17, what is WXY?<br><br> 34<br> 56<br> 17<br> 73
satela [25.4K]

Answer:

73

Step-by-step explanation:

17×2=34

180-34=146

146/2=73

=73

7 0
3 years ago
Which expression is equivalent to the value 16?
insens350 [35]

Answer:

4^2

Step-by-step explanation:

4×4 is 16

4^2 is 4 times 4

8 0
4 years ago
Read 2 more answers
When an object moves in a circle the __________ of the object is continually changing. What is the missing word in this sentence
Bezzdna [24]

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing.  This velocity is the slope of the tangent line to the curve at a given point on the curve.

3 0
3 years ago
A rectangle has a length of 12 centimeters and a width of 4 centimeters. Find the perimeter.
mamaluj [8]

Answer:


Step-by-step explanation:

Given:

Length (l) = 12 cm

Width (w) = 4 cm

Perimeter of the rectangle = 2(l + w) units

<em>P</em> = 2(12 + 4)

<em>P</em> = 2 (16)

<em>P</em> = 32

<h2><u><em>32 cm</em></u></h2>
4 0
4 years ago
Read 2 more answers
Find the Horizontal Tangent for x^3/3+3x^2-16x+9
bazaltina [42]

Answer:

The two horiz. tang. lines here are y = -3 and y = 192.

Step-by-step explanation:

Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function.  Thus, we find f '(x):

f '(x) = x^2 + 6x - 16.  This is the formula for the slope.  We set this = to 0 and determine for which x values the tangent line is horizontal:

f '(x) = x^2 + 6x - 16 = 0.  Use the quadratic formula to determine the roots here:  a = 1; b = 6 and c = -16:  the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:

      -6 plus or minus √100

x = ----------------------------------- = 2 and -8.

                         2

Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3.  So one point of tangency is (2, -3).  Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line:  it is y = -3.

Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8.  The value of x^3/3+3x^2-16x+9 at x = -8 is  192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).


3 0
3 years ago
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