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Nikolay [14]
3 years ago
14

When an object moves in a circle the __________ of the object is continually changing. What is the missing word in this sentence

?
Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing.  This velocity is the slope of the tangent line to the curve at a given point on the curve.

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9 unit percent change is 23, what is the 19th unit percent cahnge?
vichka [17]

Answer:

42.40705%

Step-by-step explanation:

(1 - (23/100)^(19/9) = 1 + r/100

0.57593 = 1 + r/100

r = 42.40705%

6 0
2 years ago
If AB = BC, AB = 4x -2, and BC = 3x + 3, find the<br> length of AB.
Valentin [98]
The length of AB is 18
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Help PLEASE!!! Math Final. ASAP!!!!!!!!!!!!
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3 years ago
a physics student stands at the top of a hill that has an elevation of 56 meters. He throws a rock and it goes up in the air and
babunello [35]
The answer is 57.04 meters. 
Solution:
The height y of the rock above the ground as a function of the horizontal distance x from the starting point on top of the hill can be modeled by the equation 
     y = -0.04x^2 + 1.3x + 56

We now set this equation equal to zero because the height of the ground where the rock will land is zero:
     0 = -0.04x^2 + 1.3x + 56

Since we have a quadratic equation, we can calculate for the horizontal distance x by using the quadratic formula     
     x = [-b ± sqrt(b^2 - 4ac)] / 2a      
     x = {-1.3 ± sqrt[1.3^2 - 4(-0.04)(56)]} / 2(-0.04)     
     x = (-1.3 ± sqrt(10.65)) / (-0.08)     
     x =  -24.54 meters or  57.04 meters
There are two solutions for x but one is negative, so we choose the positive value. 
5 0
3 years ago
Answer the question below. Be sure to show your work
likoan [24]

ANSWER:

We have to find new side-lengths of PQR triangle.

Original sides are.

\begin{gathered} PQ\text{ = 8cm} \\ QR=17\operatorname{cm} \\ RP=15\operatorname{cm} \end{gathered}

After multiplying by 2.5 we get

\begin{gathered} PQ^{\prime}=2.5\times PQ=(8\times2.5)cm=20\operatorname{cm} \\ QR^{\prime}=(17\times2.5)cm=42.5\operatorname{cm} \\ RP^{\prime}=(15\times2.5)cm=37.5\operatorname{cm} \end{gathered}

These are the new sides of the P'Q'R' triangle.

5 0
1 year ago
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