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3 years ago

How to solve d - 5 = 7 algebraically

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Simplifying

d + -5 = 7

Reorder the terms:

-5 + d = 7

Solving

-5 + d = 7

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + 5 + d = 7 + 5

Combine like terms: -5 + 5 = 0

0 + d = 7 + 5

d = 7 + 5

Combine like terms: 7 + 5 = 12

d = 12

Simplifying

d = 12

adelina 88 [10]3 years ago

6 0

Answer:

d = 12

Step-by-step explanation:

d - 5= 7

( d - 5 ) + 5 = 7 + 5

d - 5 + 5 = 12

d = 12

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<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

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Taking $b^2$ as common term,

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Taking "a" as common term,

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Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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