Answer:
Mas não reconhecida como a face da sua vida
Given:
The volume of the rectangular prism is

,
the height is h=(b+3)
1. The volume of a rectangular prism is (base area)*height
also, notice that the volume is a third degree polynomial, the height is a 1st degree polynomial, so the base area must be a 2nd degree polynomial, whose coefficients we don't know yet.
Let this quadratic polynomial be
2

notice that

is the product of the largest 2 terms:

and b, so m must be 1
also, notice that 12 is the product of the constants, k and 3
so k*3=12, this means k=4
3
we write the above equality again:


=

4
now compare the coefficient with the left side:

8=n+3
n=5
substituting n=5:
the base area is

Answer:
Answer:
<h2>MN</h2>
Step-by-step explanation:
If ΔLMN ≅ ΔXYZ, then corresponding angles and corresponding segments are congruent:
∠L ≅ ∠X
∠M ≅ ∠Y
∠N ≅ ∠Z
and
LM ≅ XY
MN ≅ YZ
LN ≅ XZ