4.4 is the answer for that problem 17.6 divided by 4
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
1a. x = 70
Alternate Interior Angles
1b. x = 120
Alternate Interior Angles
1c. x = 110
Corresponding Angles
2a. x = 100
Alternate Interior Angles
y = 80
Supplementary Angles (with x)
2b. x = 75
Corresponding Angles
y = 105
Supplementary Angles (with x)
2c. x = 70
Same-Side Interior Angles
y = 110
Supplementary Angles (with x)
Try the rest on your own!
25,000,000,000)(7,000,000