I think it is the third one. If it’s not the third one then it’s the first one.
It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = 
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
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Length = 11
Width = 9
Area we need = 126
So Area = length * width
126 = 11 * 9
Now.. this is obviously wrong.. they want us to find the correct length..
126 = L * 9
126/9 = L
L = 14
Now since they ask about how much farther you need to extend, take the final and subtract from the original
14 - 11 = 3
Answer is 3.
Answer:
-8>x>6
Step-by-step explanation:
I 5x+5I +22> 57subtract 22 on both sides
I5x+5I >35
SPLIT
5x+5>35 5x+5< -35 ( flip sign and 35 negative)
5x>30 5x< -40
x>6 x< -8
Draw a number line Write zero in the middle
From zero count to the left until- 8 make an open circle because- 8 is not included From -8 draw an arrow to the left (because x is less than -8)
From zero count to the right until 6 Make an open circle bc 6 is not included. From 6 draw an arrow to the right (because x is more than 6)
PART 2 is not already solved?
If you need to solve fot t
Divide both parts by pr
t= (l/ pr)
Answer:
Nikolai Lobachevsky and Bernhard Riemann
Step-by-step explanation:
Nikolai Lobachevsky (A russian mathematician born in 1792) and Bernhard Riemann (A german mathematician born in 1826) are the mathematicians that helped to discover alternatives to euclidean geometry in the nineteenth century.
