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Sergeeva-Olga [200]
3 years ago
14

What is the midpoint of a line segment with endpoints at (6, -4) and (15,8)?

Mathematics
1 answer:
german3 years ago
8 0

Answer:

Look at the attachment

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Is {(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)} a function
NISA [10]

Answer:

No

Step-by-step explanation:

The set contains 2 different ranges for 1 domain. In this case, X = 1 returns 5 and -3, meaning it cannot be a function.

4 0
2 years ago
Which linear equation passes through the point (10,-7)
N76 [4]
Y = -7
or
x = 10
or
y = x - 13
there can be endless answers
8 0
2 years ago
Read 2 more answers
Please please help ASAP! Classify each angle!
Olenka [21]

Answer:

<h3>             Acute Angles: ∠TLS, ∠SLT, ∠ULR</h3><h3>             Right Angles:   ---------</h3><h3>             Obtuse Angles:  ∠RLT, ∠SLU, ∠ULS,</h3><h3>             Straight Angles:  ∠RLS, ∠TLU </h3><h3>             Not angles: ∠TRL </h3>

Step-by-step explanation:

The lines intersect at point L, so all angles have a vertex (middle letter) L so there is no angle TRL

Straight angle is a line with dot-vertex, so the straight angles are ∠RLS and ∠TLU.

∠TLS is less than 90° then it is acute angle (∠SLT is the same angle). ∠ULR is vertex angle to ∠TLS, so it's also acute angle.

Two angles adding to straight angle mean that they are both right angles or one is acute and the second is obtuse. ∠TLS is acute so ∠RLT is obtuse (they adding to ∠RLS) and ∠SLU is obtuse (they adding to ∠TLU). ∠ULS is the same angle as ∠SLU.

8 0
3 years ago
(x+3)(x-3) sum of difference​
matrenka [14]
4x-sum to
The value of 7
Equals3
5 0
3 years ago
Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
navik [9.2K]

ANSWER


The possible rational roots are:


\pm\frac{1}{2},\pm2,\pm \frac{5}{2}


EXPLANATION


According to the rational root theorem, the possible rational roots of the polynomial,



4x^3+9x^2-x+10=0


are all the possible factors of the constant term divided by all the possible factors of the coefficient of the highest degree of the polynomial.



Therefore we examine the numerator and denominator of the options provided to see if they are factors of 10 and 4 respectively.



For

\pm\frac{1}{2}, we can see that 1 is a factor of 10 and 2 is a factor of 4, hence it is a possible rational root.


The same thing applies to \pm2,\pm \frac{5}{2} also.


As for


\pm \frac{2}{5}, 2 is a factor of 10 but 5 is not a factor of 2, hence it is not a possible rational root.


5 0
3 years ago
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