2 years ago

Find the distance between -23 and 17 on a number line. d =

Mathematics

1 answer:

Svet_ta [14]2 years ago

6 0

Answer:

Distance between -23 & 17 = 40

Step-by-step explanation:

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In a basketball game, Archie made 3/5 of his shots. Which numbered choice has a value that is the same as the ratio Archie made

Step2247 [10]

Answer:

0.6

Step-by-step explanation:

3/5=0.6

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2 years ago

The length of a rectangle is 3 less than twice the width. Write a function rule for the perimeter in terms of w, the width

Nitella [24]

l = 2w-3

P = 2(l+w)

substitute in for l

P = 2(2w-3 +w)

combine like terms

P = 2(3w-3)

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2 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$