Answer:
n(n+1)(n+5)/3
Step-by-step explanation:
there is no value, as we don't know n.
but we can create a summary formula/ function definition :
this is the sum for k = 1 to n of k×(k+3)
k×(k+3) = k² + 3k
so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.
and the sum of 3k is 3 times the sum of k for k=1 to n.
Σk² for k=1 to n = [n(n+1)(2n+1)]/6
Σk for k=1 to n = n(n+1)/2
3×Σk for k=1 to n = 3×n(n+1)/2
so, we have a function formula
n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =
= n(n+1)(2n+1+9)/6 = n(n+1)(2n+10)/6 = n(n+1)(n+5)/3
Answer:
see the procedure
Step-by-step explanation:
we have
step 1
Let
y=f(x)
step 2
Exchange the variables
x for y and y for x
step 3
Isolate the variable y
step 4
Let
<span>He relationship between rectangular and rotational coordinates can be represented by the vector equation:
r = xi +yj = rcos(theta)i+rsin(theta)j
What values in radians makes
x minimum
y maximum
and x = -y
Ans : x minimum = -r when theta = 180 degrees + any multiple of 360 degrees
y minimum = -r when theta = 270 degrees + any multiple of 360 degrees
x = -y when theta = 135 degrees + any multiple of 180 degrees.</span>
Answer:
6
Step-by-step explanation:
