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Bas_tet [7]
3 years ago
8

what is the distance between the points with coordinates (-5,5) and (5,-5)? express your answer in simplest radical form

Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

10 spaces in each direction

Step-by-step explanation:

                     5

                      !

-5--------------------!-------------------5

                      !

                      !

                      5

You might be interested in
Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate
Murljashka [212]

Answer:

B. \frac{25}{64}

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be \frac{10}{16} as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

P(\text{The point is not on KL)}=1-\text{probability that point is on KL}

P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}

P(\text{The point is not on KL)}=1-\frac{(8-2)}{16}

P(\text{The point is not on KL)}=1-\frac{6}{16}

P(\text{The point is not on KL)}=\frac{16-6}{16}

P(\text{The point is not on KL)}=\frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}

Therefore, our desired probability will \frac{25}{64} and option B is the correct choice.

5 0
3 years ago
Please help I need it today please help
Rufina [12.5K]
0-2+9=7 is the answer I think
6 0
4 years ago
Z=5x - 11 y<br> can someone please hell
Airida [17]

Answer:

\frac{z+11y}{5}

Step-by-step explanation:

z=5x-11y

+11y on both sides

z+11y=x

divide by 5 on both sides

<h2>\frac{z+11y}{5}</h2>
8 0
3 years ago
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ &lt; 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
4 years ago
Need help asap, Will give brainliest! please answer correctly!
Dominik [7]

Answer:

D

Step-by-step explanation:

We can solve this particular problem entirely by elimination. First, notice, that our inequality simply says the left side is <em>less than</em> the right, not <em>less than or equal to</em>. If it were less than or equal to the value on the right, it would include all of the points on the boundary line, and we'd indicate this with a solid line. In our situation, the left side is never <em>equal</em> to the right, so we'd use a dotted line to draw our boundary line. Only B and D fit the bill.

So between B and D, which one represents 4y+8? Well, setting the two sides equal to each other, we'd get the equation for a line. If (x, y) is a point on that line, then, what does mean when we say the side with y on it is less than the side with the x on it? It means we'd have to <em>decrease </em>the y value of a point on the line, which would give us a point <em>below </em>the line. So our graph has to show <em>every point below the line 4y + 8 = -3x</em>, and the only answer that represents this situation is D

5 0
4 years ago
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