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AlexFokin [52]
3 years ago
10

What is an inequality and a compound inequality

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.

Step-by-step explanation:

A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.A compound inequality contains at least two inequalities that are separated by either "and" or "or". ... A number is a solution to the compound inequality if the number is a solution to both inequalities. It can either be written as x > -1 and x < 2 or as -1 < x < 2.

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ludmilkaskok [199]

v =  \frac{4}{3} \times \pi \times  {r}^{3}

Finding the radius,

d = 2r, \: r =  \frac{d}{2}  =  \frac{8}{2}  = 4inches

Plugging in our values,

v =  \frac{4}{3}  \times 3.14 \times  {4}^{3}  =  \frac{4}{3}  \times 3.14 \times 64 = 267.95 {inches}^{3}  \\

Rounding to the nearest whol number,

v = 268 {inches}^{3}

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vesna_86 [32]

Answer:

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3 years ago
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Crank

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definitely theoretical.  Seems how mom packed the lunch 3/5 times a week, the pattern will follow

Step-by-step explanation:

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3 years ago
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podryga [215]

Answer:

2/6

Step-by-step explanation:

Ok, so if the fraction is 1/3 and the denominator needs to be 6, then what you do is figure out what would turn 3 into 6. So, 3 x 2 would equal 6 and then you would have to also keep that two and multiply that 2 with the 1 and you would get 2. That would lead to the numerator being 2 and the denominator being 6, or 2/6.

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3 years ago
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