The quadrilaterals are two congruent isosceles trap ezoids and a kite.
Find the missing dimension of trapezoid b1 = 3 m; b2= 4 m; A = 7 m 2 show your work
1 answer:
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The surface area of the triangular prism is 828 in².
Solution:
Let the missing length of the triangle be x.
Using Pythagoras theorem,
In right triangle, square of the hypotenuse is equal to the sum of the squares of other two sides.
Subtract 144 on both sides of the equation.
Taking square root on both sides, we get
x = 9
The missing length of the triangle is 9 in.
Area of the front triangle =
= 54 in²
Area of the back triangle =
= 54 in²
Area of the sloping rectangle = 20 × 9
= 180 in²
Area of the back rectangle = 20 × 12
= 240 in²
Area of the base rectangle = 20 × 15
= 300 in²
Total area = 54 in² + 54 in² + 180 in² + 240 in² + 300 in²
= 828 in²
The surface area of the triangular prism is 828 in².