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evablogger [386]
3 years ago
5

In an all boys school, the nights of the student body are normally distributed with a mean of 71 inches and a standard deviation

of 3 inches. Using the empirical rule, what percentage of the boys are between 65 and 77 inches tall?
Mathematics
1 answer:
schepotkina [342]3 years ago
3 0
The answer is 77inches towards
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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
Serga [27]

Answer:

Price of advance ticket: 15$

Price of same-day ticket: $40

Step-by-step explanation:

Let y be the price of one advance ticket and x the cost of one same day ticket.  

We know that the combined cost of one advance ticket and one same-day ticket is $55, so

y+x=55 equation (1)

We also know that 20 advance tickets and 35 same-day tickets cost $1700, so

20y+35x=1700 equation (2)

Now, let's solve our system of equations step-by-step:

step 1. Solve for x in equation (1)

y+x=55

x=55-y equation (3)

step 2. Replace equation (3) in equation (2)

20y+35x=1700

20y+35(55-y)=1700

20y+1925-35y=1700

-15y=-225

y=\frac{-255}{-15}

y=15 equation (4)

step 3. Replace equation (4) in equation (3)

x=55-y

x=55-15

x=40

We can conclude that the price of one advance ticket is $15 and the price of one same-day ticket is $40.

7 0
3 years ago
Evaluate the following.<br> |−9|−|6-11|<br> can u guy's explain how to do it
puteri [66]
|-9|-|6-11|=\\&#10;9-|-5|=\\&#10;9-5=\\&#10;4
8 0
4 years ago
I need help with this ASAP and can you explain so i can understand?!
Elanso [62]

Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0
3 years ago
Read 2 more answers
Find Y NOW!!! Please
Vladimir79 [104]

Answer:

Y

Step-by-step eon:

6 0
4 years ago
−5(1−5k)−4(2k+5) pleas
Kazeer [188]

Answer:

<h2>33k - 25</h2>

Step-by-step explanation:

-5(1 - 5k) - 4(2k + 5)      <em>use distributive property a(b + c) = ab + ac</em>

= (-5)(1) + (-5)(-5k) + (-4)(2k) + (-4)(5)

= -5 + 25k - 8k - 20           <em>combine like terms</em>

= (25k - 8k) + (-5 - 20)

= 33k - 25

5 0
4 years ago
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