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jeyben [28]
3 years ago
12

Simplify 8c^3d^2 4cd^2

Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer:

2 {c}^{2}

Step-by-step explanation:

\frac{8 {c}^{3}  {d}^{2} }{4 {c}^{1} {d}^{2}  }  \\  = 2 {c}^{3 - 1}  {d}^{2 - 2}  \\  = 2 {c}^{2} {d}^{0}

we know that,

{d}^{0}  = 1

so,

= 2 {c}^{2}  {d}^{0}  \\  = 2 \times  {c}^{2}  \times 1 \\  = 2 {c}^{2}

hope this helps

brainliest appreciated

good luck! have a nice day!

Neko [114]3 years ago
6 0

Answer:

2c^{2}

Step-by-step explanation:

\frac{8c^33d^2}{4cd^2}

\frac{2c^2d^0}{1}

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When a teacher counted her student in group 4. There were 2 students left over.When she counted them in groups of 5.She had I st
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Number of students in her class = x students

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This means x is an even number because multiples of 4 are even and adding 2 does not change its parity.

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Answer:

<h2>A. R=1098.7ft</h2><h2>B. H=274.7ft</h2>

Step-by-step explanation:

<em>"The question is not complete, here is the complete question</em>

<em> The range R and the maximum height H of a projectile fired at an inclination θ to the horizontal with initial speed v0 are given by the formulas​ below, where g≈32.2 feet per second per second is the acceleration due to gravity. Complete parts A and B.</em>

<em />R=\frac{2v_o^2sin \theta cos \theta}{g}<em />

<em />H=\frac{v_o^2sin^2 \theta}{2g}<em />

<em>A. Find the range R if the projectile is fired at an angle 45° to the horizontal with an initial speed of 190 ft per second</em>

<em>B. Find the maximum height H  if the projectile is fired at angle 45° to the horizontal with an initial speed of 190 ft per second"</em>

<em />

<u>Solution</u>

A. given the expression for Range R

substitute v= 190 ft/sec and ∅=45°

R=\frac{2(190)^2sin(45) cos(45)}{32.2}\\\\R=\frac{72200*0.7*0.7}{32.2}\\\\R=\frac{35378}{32.2} \\\\R=1098.7ft

B. . given the expression for maximum height

substitute v= 190 ft/sec and ∅=45°

H=\frac{v_o^2sin^2 \theta}{2g}\\\\H=\frac{190*190*0.7*0.7}{2*32.2}\\\\H=\frac{17689}{64.4}\\\\H=274.7ft

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