Question

He range R and the maximum height H of a projectile fired at an inclination θ to the horizontal with initial speed v0 are given by the formulas​ below, where g≈32.2 feet per second per second is the acceleration due to gravity. Complete parts A and B. R= 2v20sinθcosθ g H= v20sin2θ 2g

Answer 1

Answer:

A. R=1098.7ft

B. H=274.7ft

Step-by-step explanation:

"The question is not complete, here is the complete question

The range R and the maximum height H of a projectile fired at an inclination θ to the horizontal with initial speed v0 are given by the formulas​ below, where g≈32.2 feet per second per second is the acceleration due to gravity. Complete parts A and B.

$R=\frac{2v_o^2sin \theta cos \theta}{g}$

$H=\frac{v_o^2sin^2 \theta}{2g}$

A. Find the range R if the projectile is fired at an angle 45° to the horizontal with an initial speed of 190 ft per second

B. Find the maximum height H  if the projectile is fired at angle 45° to the horizontal with an initial speed of 190 ft per second"

Solution

A. given the expression for Range R

substitute v= 190 ft/sec and ∅=45°

$R=\frac{2(190)^2sin(45) cos(45)}{32.2}\\\\R=\frac{72200*0.7*0.7}{32.2}\\\\R=\frac{35378}{32.2} \\\\R=1098.7ft$

B. . given the expression for maximum height

substitute v= 190 ft/sec and ∅=45°

$H=\frac{v_o^2sin^2 \theta}{2g}\\\\H=\frac{190*190*0.7*0.7}{2*32.2}\\\\H=\frac{17689}{64.4}\\\\H=274.7ft$