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lidiya [134]
3 years ago
12

Which equation matches the graph?

Mathematics
1 answer:
ipn [44]3 years ago
4 0
The equation that matches the graph is the second one !
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For a special event, a restaurant charges a one-time setup fee, plus a charge for each person attending the event. The charge fo
Rashid [163]

Any linear function is of the form y=mx+b

Here m is slope and b is y intercept.

Slope is difference in y divided by different in x values .

In the question for 5 persons cost is $100 and for 10 persons cost is $162.50

So the points are (5,100) and (10,162.50)

Slope m=\frac{162.50-100}{10-5}=12.50

We can find the value of b by taking m=12.50 and (x,y)=(5,100)

Substitute these values in y=mx+b

100=12.50(5)+b

100=62.50+b

Subtracting 62.50 both sides

b=100-62.50

b=37.5

a) Put m=12.50 and b=37.50 to get the equation

y=12.50x+37.50

b)Rate of change is the m value or the slope of the function.

Initial value that is (5,100) gives us one of the points to find the rate of change.

7 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS
Jlenok [28]

Answer:

its B

Step-by-step explanation:

6 0
3 years ago
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Let k ( x ) = 2 x + 3 and m ( x ) = 3 x 2 + 7 x − 10 . Find the indicated value. M ( k ( − 4 ) ) =
murzikaleks [220]

Answer: 30

Step-by-step explanation:

Given

k(x)=2x+3

M(x)=3x^2+7x-10

M\left(k(x)\right) is given by replacing the x by k(x) from the M(x)

\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38

Now, M\left(k(-4)\right) is

\Rightarrow M\left(k(-4)\right)=12(-4)^2+50(-4)+38\\\Rightarrow M\left(k(-4)\right)=192-200+38\\\Rightarrow M\left(k(-4)\right)=30

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3 years ago
Find the coordinates of the circumcenter of the triangle below
Lena [83]
(2,2) (6,2) (6,8) Hope this helps I’m pretty sure this is correct :)
6 0
3 years ago
Each of the students im Romi's class raised at least $25 during the jump-a-thon. What is the least amount of money the class rai
EastWind [94]
If each of the 28 students made at least $25, you would multiply 28 and 25 together to obtain the least amount of money the class raised. That gets, 28x25 = 700. The class made at least $700.
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