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2 years ago

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10. A trapezoid has base lengths of 24 units and 20 units. The height of the trapezoid is one-half as long as the

2 answers:

cricket20 [7]2 years ago

7 0

Answer:

The longer base given: 24. Get the height by taking half of that.

Use the formula for the area of a trapezoid $A = \frac{b_{1} +b_{2} }{2} (h)$

Step-by-step explanation:

lana [24]2 years ago

6 0

Answer:

264 units.

Step-by-step explanation:

since the two bases are 20 and 24, the shorter base is usually the shorter number, so the shorter base is 20 units. Which means, the longer base is 24 units. So, half of 24 is 12. So, the height is 12. Then I used to calculator, my results are in the picture below.

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antoniya [11.8K]

The similar circles P and Q can be made equal by dilation and translation

The horizontal distance between the center of circles P and Q is 11.70 units
The scale factor of dilation from circle P to Q is 2.5

<h3>The horizontal distance between their centers?</h3>

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

<h3>The scale factor of dilation from circle P to Q</h3>

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

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Step-by-step explanation:

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Without solving the equations which answer best describes the solutions.

telo118 [61]

ANSWER:
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2 years ago

DochEvi [55]

For the first figure the Circumference of the circle is: 5.3 $\ip$ $\pi$ cm.

For the second figure the Circumference of the circle is: 80 $\ip$ $\pi$ inch.

<h3>What is Circumference of the Circle?</h3>

The circumference of a circle is defined as the linear distance around it.

i.e., $C= 2 *\pi*r$

For First Figure,

Circumference of the circle:

$= 2 *\pi*r$

$= 2 *\pi* \frac{5.3}{2}$

$= 2 *\pi*2.65$

$Circumference= 5.3*\pi cm$

For the second Figure,

Circumference $= 2 *\pi*r$

$= 2 *\pi*40$

$= 80 *\pi$

$Circumference =80\pi \;inch$

For the first figure the Circumference of the circle is: 5.3 $\ip$ $\pi$ cm.

For the second figure the Circumference of the circle is: 80 $\ip$ $\pi$ inch.

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