Answer:
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Answer: maximum "safe" Force = 415.58 N
Step-by-step explanation:
<u>Length = 1.2 m</u>
lower bound is 1.15 (because it rounds up to 1.2)
upper bound is 1.24 (because it rounds down to 1.2)
<em>Note: 1.25 would round up to 1.3</em>
<u>width = 2.5 m</u>
lower bound is 2.45 (because it rounds up to 2.5)
upper bound is 2.54 (because it rounds down to 2.5)
<em>Note: 2.55 would round up to 2.6</em>
<u>Pressure = 150 N/m²</u>
lower bound is 147.5 (because it rounds up to 150)
upper bound is 152.4 (because it rounds down to 150)
<em>Note: 152.5 would round up to 155</em>
<u>Max "safe" Force means minimum Area and minimum Pressure (lower bounds)</u>
Force = Area x Pressure
= length x width x Pressure
= 1.15 x 2.45 x 147.5
= 415.58
We have been given angle A as 75 degrees and sides a = 2 and b = 3.
Using Sine rule, we can set up:
Upon substituting the given values of angle A, and sides a and b, we get:
Upon solving this equation for B, we get:
Since we know that value of Sine cannot be more than 1. Hence there are no values possible for B.
Hence, the triangle is not possible. Therefore, first choice is correct.
For the first one, f(x) clearly has positive y values, while g(x) doesn't (from what I see). In addition, cos(x) has a range of [-1, 1] so 2cosx would have a range of [-2, 2] and 2cosx+1 would therefore have a range of [-3, 3]. In addition, the maximum of the graph shown is 3, so the answer would be f(x) and h(x)
For the second one, sin(x) (including any x value)has a range of [-1, 1] so 2sinx would have a range from [-2, 2] and the range for 2sinx-2 would be
[-4, -2] with the minimum being -4. For g(x), squaring something makes it positive, meaning that the minimum of (x-3)^2 would be 0. 0-1 would be -1. For h(x), the lowest is clearly -6, and -6 is lower than both -1 and -4, mking h(x) the smallest
Answer:
Step-by-step explanation:
For the sake of clarity, assuming you meant:
1) Absolute Value or Modulus functions has one property that assures us that:
2) Solving for x
Not defined in Real Set of Numbers
Evaluating :
3) So, since for the first case the Discriminant Δ <0, then the solutions presented for . The only solution in the Real Set for the inequality is , i.e. x=-1.