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bekas [8.4K]
3 years ago
13

Rohit takes4 4/5minutes to make a complete round of a circular park.How much time hi will take to make 15rounds​

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

Rohit takes 4 4/5 minutes ( =4.8 minutes) to make a complete round of a circular park. For finishing 15 rounds, he needs time T:

T = 15 x 4.8 = 72 minutes

Hope this helps!

:)

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the population of a town is 1,03.500 if 56%of the population is male find the number of females in the town
bija089 [108]
The population you gave isn't formatted correctly so I'll solve the problem assuming you mean 103,500.

First we find the number of males from the percentage given:

0.56 * 103500 = 57960 males

Subtract the number of males from the total population to get the number of females:

103500 - 57960 = 45540 females

You could solve the problem by finding the percentage of females first. Since there are 56% males, that means there are 100-56 = 44% females.

0.44 * 103500 = 45540

The answer is 45540.




8 0
3 years ago
An athlete earns $350,000 each year. If his team makes the play-offs, he will earn a 15% bonus. What will be his total earnings
Komok [63]
15% of $350,000 is $52,500. so you add $52,500 to $350,000 and you get $402,500
4 0
3 years ago
-10+5=7x-4<br>how to i explain this step by step​
olasank [31]

Answer:

5/7 x 4 = 2.8571 in decimal form.

8 0
3 years ago
Read 2 more answers
The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).
melamori03 [73]
<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

6 0
4 years ago
What is the answer to X(x+7)
LekaFEV [45]

Answer:

\boxed{ \bold{ \boxed {\huge{ \sf{ {x}^{2}  + 7x}}}}}

Step-by-step explanation:

\sf{x(x + 7)}

Distribute x through the parentheses

\dashrightarrow{ \sf{x \times x + x \times 7}}

\dashrightarrow{ \boxed{ \sf{ {x}^{2}  + 7x}}}

Hope I helped!

Best regards! :D

3 0
3 years ago
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