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Anastasy [175]
3 years ago
11

A student in wildlife management studied trout habitat in the upper Shavers Fork watershed in West Virginia. The springtime wate

r pH of 29 randomly selected tributary sample sites were found to have the following values:
6.2 6.3 5.0 5.8 4.6 4.7 4.7 5.4 6.2 6.0 5.4 5.9 6.2 6.1 6.0 6.3 6.2 5.8 6.2 6.3 6.3 6.3 6.4 6.5 6.6 6.1 6.3 4.4 6.7
Do the data of Exercise 17.8 (above) give good reason to think that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. (A neutral pH is the pH of pure water, pH 7.)
Step 1:
STATE: Is there evidence that the springtime water pH of the Shavers Fork watershed is not neutral (pH 7)?
FORMULATE: State hypotheses to be tested.
A. H 0 : μ = 7 vs. Ha : μ > 7
B. H 0 : μ = 7 vs. Ha : μ < 7
C. H 0 : μ = 7 vs. Ha : μ ≠ 7
D. H 0 : μ ≠ 7 vs. Ha : μ < 7
Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

C. H 0 : μ = 7 vs. Ha : μ ≠ 7

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

Step-by-step explanation:

The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7

In symbols it will be written as

H0: : μ = 7 vs. Ha : μ ≠ 7

So choice C is the best option for this hypothesis testing.

Let the significance level be 0.05

The degrees of freedom = n-1= 29-1 = 28

The critical value is  t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.

The test statistic to use is t- test

t= x- u/ s/√n

The total sum is 170.9 and mean = x= 5.893

The u = 7

And the sample standard deviation is =s= 0.63

Putting the values

t= 5.893-7/0.63/√29

t= - 1.107/0.11699

t= -9.4623

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

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Nookie1986 [14]

Hey there! I'm happy to help!

We see that Noah rides his motorcycle 90 miles is 2 hours and 30 minutes, which is 150 minutes. We want to find his mph. To find this his mph, we want to find how far he has gone in one hour.

How much bigger is 150 than 60?

150/60=2.5

150 is 2.5 times bigger than 60. This means that we need to divide 90 by 2.5 to figure out how far Noah rode in 1 hour.

90/2.5=36

Therefore, Noah's average speed is 36 mph.

Have a wonderful day! :D

6 0
3 years ago
3(1)+2(_)=6<br><br> plz help on filling in the blank
TEA [102]

Answer:

x = 3/2

Step-by-step explanation:

Let's solve your equation step-by-step.

(3)(1)+2x=6

Step 1: Simplify both sides of the equation.

(3)(1)+2x=6

3+2x=6

2x+3=6

Step 2: Subtract 3 from both sides.

2x+3−3=6−3

2x=3

Step 3: Divide both sides by 2.

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Hope this helps :)

7 0
3 years ago
The negative sign in 15t-2t belongs to the term____?
alexdok [17]

The expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

Solution:

Given expressions are 15t – 2t and 2t – 15t.

To determine 15t – 2t is equivalent to 2t – 15t or not.

Substitute t = 2 in above two expressions.

15t – 2t = 15(2) – 2(2)

            = 30 – 4

            = 26

2t – 15t = 2(2) – 15(2)

            = 4 – 30

            = –26

The values of the expressions are different when t = 2.

So, 15t – 2t is not equivalent to 2t – 15t.

Hence the expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

7 0
3 years ago
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larisa [96]
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8 0
3 years ago
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kow [346]

Answer:

y = -2

Step-by-step explanation:

The midline is the horizontal line that passes exactly in the middle between the graph's maximum and minimum points.

From inspection, curve has a maximum at y = 1 and a minimum at y = -5

The midline between these is y=\frac{1-5}{2}=-2

So the equation for the midline of this graph is y = -2  (shown in red on the attached graph)

6 0
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