Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:
![A=\frac{3\sqrt{3}}{2} a^2](https://tex.z-dn.net/?f=%20A%3D%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D%20a%5E2%20%20%20)
Where
is the area of the regular hexagon
is the side length of the regular hexagon
Also, it's Perimeter is given by:
![P=6a](https://tex.z-dn.net/?f=%20P%3D6a%20)
Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.
A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.
Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.
Let us now find the distance between the points D and E using the distance formula which is as:
![d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=%20d%3D%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%20%20)
Where
is the distance.
and
are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance
)
Applying the above formula we get:
![d=\sqrt{(8-4)^2+(0-0)^2} =\sqrt{4^2}=4](https://tex.z-dn.net/?f=%20d%3D%5Csqrt%7B%288-4%29%5E2%2B%280-0%29%5E2%7D%20%3D%5Csqrt%7B4%5E2%7D%3D4%20%20)
![\therefore d=4](https://tex.z-dn.net/?f=%20%5Ctherefore%20d%3D4%20)
We know that this distance is the side length of the given regular hexagon.
![\therefore d=a=4](https://tex.z-dn.net/?f=%20%5Ctherefore%20d%3Da%3D4%20)
Now, if the sides of the given regular polygon are reduced by 40%, then the new length of the sides will be:
![a_{small}=4-\frac{40}{100}\times 4=2.4](https://tex.z-dn.net/?f=%20a_%7Bsmall%7D%3D4-%5Cfrac%7B40%7D%7B100%7D%5Ctimes%204%3D2.4%20%20)
Thus, the area of the smaller hexagon will be:
unit squared
and the new smaller perimeter will be:
unit
Which are the required answers.