Answer:
50
Step-by-step explanation:
would it be 50 because you the q to the power of 2 is 2q. Then you would subtract to the other side of the equation so it would be -100=-2q. After you would divided the -2 in -2q on both sides and -100/-2 is 50. So your answer is q=50
Answer:
20
Step-by-step explanation:
y^2+4y-1=(-7)^2+4(-7)-1=(-7)(-7)-28-1=49-28-1=21-1=20
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
1. A. 10,000
Explanation: 10^4 = 10,000
2. x = -12
Explanation: see photo
Answer:
590
Step-by-step explanation:
To the ten that is nearest to 593