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Svetllana [295]
4 years ago
14

Find the point of diminishing returns (x comma y )for the function​ R(x), where​ R(x) represents revenue​ (in thousands of​ doll

ars) and x represents the amount spent on advertising​ (in thousands of​ dollars).

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
4 0

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The point of diminishing returns (x , y ) is  (11, 21462)

Step-by-step explanation:

From the question we are told that

     The function is  R(x) =  10,000 -x^3 - 33x^2 + 800x ,  \ \ 0 \le x \le 20

Here R(x)  represents revenue (in thousands of​ dollars) and  x  represents the amount spent on advertising​ (in thousands of​ dollars).

           Now  differentiating  R(x) we have  

               R'(x) =  -3x^2 +66x + 800

Finding the second derivative of R(x)

              R''(x) =  -6x +66

at  inflection point    R''(x) =  0

    So      -6x  +66  = 0

=>           x=  11

    substituting value of x into R(x)

     R(x) =  10,000 -(11)^3 - 33(11)^2 + 800(11) ,

      R(x) = 21462

Now the point of diminishing returns (x , y ) i.e (x , R(x) ) is

     (11, 21462)

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1. P(X>69)=P(Z>-1.136)=1-P(Z

2. P(X

3. P(52.6 \leq X \leq 105.4)=P(-3

Step-by-step explanation:

Assuming the value for the mean 79 and the deviation 8.8

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the amount of collagen of a population, and for this case we know the distribution for X is given by:

X \sim N(79,8.8)  

Where \mu=79 and \sigma=8.8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z-1.136)

And we can find this probability on this way:

P(Z>-1.136)=1-P(Z

3) Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(Z

4) Part c

We need to find first the limits for 3 deviations within the mean

\mu -3 \sigma = 79-3(8.8)=52.6

\mu +3 \sigma = 79+3(8.8)=105.4

P(52.6

And we can find this probability on this way:

P(-3

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-3

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