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3 years ago

Find the missing terms in the equation so that it is true. b (3x−5)^2=(? + ?? +25)

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

7 0

Answer:

9x^2 and -30x

Step-by-step explanation:

Basically, what we want to do is expand out (3x - 5)^2, which is the same as (3x - 5)(3x - 5).

Use FOIL (first, outer, inner, last):

- the first terms are 3x and 3x, so multiply those together: 3x * 3x = 9x^2

- the outer terms are 3x and -5, so multiply those: 3x * (-5) = -15x

- the inner terms are -5 and 3x, so multiply those: (-5) * 3x = -15x

- the last terms are -5 and -5, so multiply those together: (-5) * (-5) = 25

Add all these together:

9x^2 + (-15x) + (-15x) + 25

9x^2 - 30x + 25

The missing terms are thus 9x^2 and -30x.

vitfil [10]3 years ago

4 0

Answer:

9x², -30x

Step-by-step explanation:

(3x−5)^2=(? + ?? +25)

(3x)² - 2(3x)(5) + (5)²

9x²- 30x + 25

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How do you find the complex and real roots for x^4-3x^2+2=0

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X^4 - 3x^2 + 2 = 0
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