4 years ago

How do you find the complex and real roots for x^4-3x^2+2=0

1 answer:

6 0

X^4 - 3x^2 + 2 = 0
(x^2 - 2)(x^2 - 1) = 0

so either x^2 - 2 = 0 or x^2 - 1 = 0

so x^2 = 2 or x^2 = 1

so x = sqrt 2 , - sqrt2, 1 , -1 Answer

all the roots are real

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