Question

A marble is selected at random from a jar containing 2 red marbles, 3 yellow marbles,

Answer 1

Answer:

see below

Step-by-step explanation:

2 red marbles, 3 yellow marbles, and 6 green marbles = 11 marbles

a P(red) = red/total = 2/11

b) P(not yellow) = (total - yellow)/total = (11-3)/11 = 8/11

c) P(red or green) = (red or green)/total = (2+6)/11 = 8/11

d) P( not red or green) = P(yellow) = yellow/total = 3/11