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3 years ago

PLEASE HELP WILL MARK BRAINLIESTFind the area of the right triangle.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

4 0

Answer:

Step-by-step explanation:

This right triangle is on a grid.

The area is the height * base/2

The base is on a line segment parallel to the x axis which is 6 squares.

The height is on a line segment parallel to the y axis which is 2 squares

The area is the height * base /2

Area = 6 * 2 /2 = 12/2 = 6 square units.

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Help!!!! Somebody help me solve these questions please

kykrilka [37]

Step-by-step explanation:

Area of a trapezium = SOPS/2 × ph

Sops is the sum of 4+10 = 14

14/2 is 7. 7×4 = 28

A = 28cm²

Area = L×W

10×6= 60cm²

5 0

3 years ago

Read 2 more answers

Solve for x. Round your answer to the nearest hundredth.

Vinil7 [7]

Answer:

14: 2x-1 = 3

2x=4

x=2

15:

x = 1/2500000

16: (ln(4/3))/4

17: sqrt(5e^12)

18: x = 16, -4

3 0

3 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$