A) What time of the day do my friends eat their biggest meal?
<span>B) How many times each week do my friends eat out? </span>
<span>C) What types of foods do my friends prefer?
</span>
Answer:
Explanation:
fg(x) = (x+2)(3x^2 - 1)
= 3x^3 - x + 6x^2 - 2
= 3x^3 + 6x^2 - x - 2
gf(x) = (3x^2 - 1)(x + 2)
= 3x^3 + 6x^2 - x - 2
As you can see:
fg(x) = gf(x)
3x^3 + 6x^2 - x - 2 = 3x^3 + 6x^2 - x - 2
Answer: area is 286.16 ft²
Step-by-step explanation:
Length of the sand pit is 29.2 feet and the width is 9.8 feet.
L= 29.2 ft
W = 9.8 ft
To find out the area, all we have to do is multiply the lenght by the width:
And do not forget that to calculate the area, all units must be the same and for the area, it is always the unit squared, in this case, feet square or simply (ft²).
A = l*w
A = 29.2 * 9.8 = 286.16 ft²
Answer:
379.56ft²
Step-by-step explanation:
Oh lordy why, okay we got this:
So we're going to start with the area of the square, this is easy because all of the sides are 25ft, so we just have to plug into our formula for squares (base x height):
25 x 25 = 625
Now we have to do the semicircle, remember that the formula for the area of a circle is pi x radius², we're using 3.14 for pi, so we have to find the radius (half the diameter):
25 ÷ 2 = 12.5
12.5² = 156.25
3.14 x 156.25 = 490.625
Normally we would stop here, but because this is only a semicircle, we have to divide by two:
490.625 ÷ 2 = 245.3125
So, now that we have our two areas, we have to subtract the semicircle from the square:
625 - 245.3125 = 379.6875
Now, I realize that his answer isn't in your cute little word bank, but that because I rounded pi, so the closest is 379.56
So, the area of the figure is 379.56ft²
if this is wrong let me know so I can fix it
hope this helps:)
1) in order to solve this problem you must to obtain The value of K, for it you know by definition that the horizontal slope of the side BC is zero ,
then m = Y2-Y/X2-X1, 0 = 5-K/4-6⇒0 = 5-K⇒K = 5
known this value for K you ca find the equation of thE line that pass through A and C
2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)
m= 5-1/4-(-2) = 2
now with any point A or C and the slope you obtain the line
A(-2,1)
y-y1 = m (x-x1) , Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3
