Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.
1 answer:
Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.
You might be interested in
Answer:
Step-by-step explanation:
From Bayes' theorem is stated mathematically as the following equation:[2]
{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}
where A and B are events and P(B) ≠ 0.
P(A) and P(B) are the probabilities of observing A and B without regard to each other.
P(A | B), a conditional probability, is the probability of observing event A given that B is true.
P(B | A) is the probability of observing event B given that A is true.
At this point, go through the attached file before you continue with part B.
Part B)
P(silver) = P(silver from SS)+P(silver from GS)
note P(SS)=P(GG)=P(GS) = 1/3
P(silver from SS) = 1
P(silver from GS) = 1/2
hence
P(Silver from SS) = 1/3
P(Silver from GS) = 1/3 *1/2
P(Silver) = 1/3*1+1/3*1/2
required probability = P(Silver from SS)/P(Silver) = 2/3
