Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.
1 answer:
Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.
You might be interested in
The given expression is
We need to determine the expression as an equivalent algebraic expression involving only x.
The expression has to be expressed as an algebraic expression in x.
Thus, we have;
Using the identity in the above expression, we get;
Simplifying, we get;
Hence, the expression can be written as