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amid [387]
3 years ago
11

Luke bought three canvas boxes to store his papers. The canvas boxes have dimensions of 12 inches by 10 inches by 12 inches. Wha

t volume of items can the three canvas boxes hold? 32 Inches cubed 102 Inches cubed 1,440 Inches cubed 4,320 Inches cubed
Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer: 4,320 inches cubed.

Step-by-step explanation:

step 1----- Volume of 1 canvas box

Volume of solid  for a rectangular box = Length x width xHeight

where  Length= 12inches,

Width= 10 inches

Height= 12 inches

Volume  of a Canvas box= 12 X 10 X 12= 1440 inches cubed

Step 2== Volume of 3 canvas boxes

1 canvas box = 1440 inches cubed

therefore 3 canvas boxes =

1440 x 3= 4320 inches cubed.

snow_tiger [21]3 years ago
4 0

Answer:

4,320

Step-by-step explanation:

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Find the area of the circle. Diameter = 12 mi<br><br> answer choice:<br> 36π mi<br> 144π mi
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3 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
Minchanka [31]

Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

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Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

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3 years ago
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