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Jet001 [13]
3 years ago
14

What is a in this equation –6(2 + a) = –48

Mathematics
2 answers:
Verizon [17]3 years ago
5 0

Answer:

a=6

Step-by-step explanation:

-6(2+a)=-48\\-6*2 = -12\\-6*a = -6a\\\rightarrow -12-6a=-48\\-12+12-6a=-48+12\\\rightarrow-6a=-36\\\frac{-6a}{-6}=\frac{-36}{-6}  \\\boxed {a=6}

<em>Brainilest Appreciated! </em>

Debora [2.8K]3 years ago
4 0
-12 -6a =-48
-6a= -48 +12
-6a= -36
Divise both sides by -6
A= 6
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3xy + 5 if x = -4, y = 2
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it will be -19

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The table shows the relationship
Airida [17]

The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0

  • Change in weight per day of hibernation = - 0.03
  • Change in weight for 115 days = - 3.45 ounces

A linear model can be created using the data in the table given using a regression calculator or excel ;

The linear model obtained in the form y = m + bx is :

  • y = - 0.03x + 0
  • y = change in weight
  • x = number of days of hibernation
  • Intercept = 0
  • Slope = -0.03

  • The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.

  • Using the regression equation, substitute, the vlaue of x = 115
  • -0.03(115) + 0 = - 3.45

Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.

Learn more :brainly.com/question/18405415

8 0
2 years ago
Help! Kinda on a rush with this quiz!
Natasha2012 [34]
B



Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
8 0
2 years ago
Two boxes have the same volume. One box has a base that is 5\text{ cm}5 cm5, start text, space, c, m, end text by 5\text{ cm}5 c
sveticcg [70]

Answer:

4times tall

Step-by-step explanation:

Volume of the boxes = Base area × height

Volume of the first box V1 = A1h1

Given the base of the first box to be 5cm, the base area:

A1 = 5cm×5cm = 25cm²

Volume of the first box V1 = 25h1... 1

Similarly, volume of the second box

V2 = A2h2

Given the base of the second box to be 10cm, the base area:

A2= 10cm×10cm = 100cm²

Volume of the second box

V2 = 100h2... 2

If the two boxes have the same volume, then V1 = V2

25h1 = 100h2

divide both sides by 25

25h1/25 = 100h2/25

h1 = 4h2

Since the height of the smaller box is represented as h1, then the height of the smaller base is 4 times tall.

3 0
3 years ago
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