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gregori [183]
3 years ago
11

Making Friends Online

Mathematics
1 answer:
Mkey [24]3 years ago
5 0

Answer:

Step-by-step explanation:

) Do you expect the distribution of number of friends made online to be symmetric, skewed to the right, or skewed to the left?

Skewed to the left.

Symmetric

Skewed to the right.

(b) Two measures of center for this distribution are 1 friend and 5.3 friends. Which is most likely to be the mean and which is most likely to be the median?

Mean=

Median=

<h2>----------------------------------</h2>

a)

as proportion of people with 0 friends is 43% whcih is on left side and maximum ; and % decrease with increasing number of friends

skewed to the right

b)

as it is skewed to the right ; therefore mean is greater than median

mean=5.3

median=1

[since for skwewed to the right distribution :mean is always greater than median, therefore higher value should be mean which is 5.3 and lower value is median which is 1]

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718.012 in expanded form and written form
Temka [501]

Answer:

y=718.012

Step-by-step explanation:

5 0
3 years ago
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If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime
Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers r and s.

To check whether \small \frac{r}{s} is an integer:

Condition (1):

Every factor of s is also a factor of r.

r \geq s

Let us consider an example:

s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2

\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10

which is an integer.

Actually, in this situation s is a factor of r.

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

r = 2^2\cdot 5\\s =2^4\cdot 5

\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

8 0
3 years ago
We have just moved to geometry. <br> Any help? <br><br> This is just practice as well
Vera_Pavlovna [14]

Answer:

rotation of 270 counterclock wise

Step-by-step explanation:

Since none of the other ones are correct and man i miss geometry i'm in Ap calc and i don't recommend haha.

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3 years ago
Jim wanted to find out what the audience thought about the debate. After the event, Jim stood at the exit to survey every fifth
balu736 [363]

Answer: D. This was a random sample. It may have included anyone in attendance.

Step-by-step explanation:

The options are:

A. This was a biased sample. Jim should interview all in attendance.

B. This was a census. Any guest may have participated.

C. This was a random sample. It may not have included anyone in attendance.

D. This was a random sample. It may have included anyone in attendance.

A random sampling is simply referred to as a subset of individuals that are picked from a larger set of individuals.

With regards to the question, Jim wanted to find out what the audience thought about the debate and after the event, he stood at the exit to survey every fifth guest.

This means that it was a random sampling and anyone could have been picked, the sampling wasn't bias.

7 0
3 years ago
When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?
Radda [10]
The correct answer for this question is this one: "B. increase your scale values"

<span>When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by </span><em>increasing your scale values</em>
Hope this helps answer your question and have a nice day ahead.
5 0
3 years ago
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