Question

What is the answer to this question.

Answer 1

Answer:

3.6

Step-by-step explanation:

It can be seen from the diagram that ΔDAC and ΔABD are right angled triangle.

Using the SOH, CAH, TOA trigonometry identity on ΔDAC where;

AC is the hypotenuse = 5.1

CD is the opposite (since it faces the angle directly)

According to SOH;

Sin$\theta$ = opp/hyp

sin$\theta = \frac{3.2}{5.1}$

$sin\theta = 0.6275\\\theta = sin^{-1} 0.6275\\\theta = 38.9^{0}$

∠DAC = ∠BAD = 38.9°

According to ΔABD, the opposite side is DB which is unknown and the hypotenuse id AB i.e 5.7

Using SOH;

$sin BAD = opp/hyp\\sin \theta = BD/AB\\sin 38.9^{0} = BD/5.7\\BD = 5.7 sin 38.9^{0}\\BD = 3.58$

BD ≈ 3.6 to one dp