This should be correct I am sorry if it is not.
<span>-0.01511422733</span>
If you want the answer in point slope form then,
y-y1 = m(x-x1)
y-c = m(x-a)
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If you want the answer in slope intercept form, then solve for y
y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)
For this answer in slope intercept form the slope is m and the y intercept is c-ma
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If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.
y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma
Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.
Answer:
8
Step-by-step explanation:
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Answer:16:18
Step-by-step explanation:
Answer: The equation of a circle with center (h,k) and radius r is given by (x−h)2+(y−k)2=r2 . For a circle centered at the origin, this becomes the more familiar equation x2+y2=r2
Step-by-step explanation: