All categories

2 years ago

What’s the correct answer for this?

Mathematics

2 answers:

Goryan [66]2 years ago

6 0

Answer:

Step-by-step explanation:

Applying the tangent-secant theorem, we get:

12^2 = 8 * (x + 10)

144 = 8x + 80

= 8x = 144 - 80

8x = 64

x = 8

Putting x = 8 in ED, which is x + x + 10, we get:

= 8 + 8 + 10

= 26

Hope this helps!

exis [7]2 years ago

5 0

Answer:

ED = 26

Step-by-step explanation:

Using tangent-secant theorem

(12)²=(8)(x+10)

144=8x+80

144-80=8x

8x = 64

x=8

Now

ED = 8+8+10

ED = 26

You might be interested in

Solving systems of equations by substitution -2x-3(6-11)=-7

Papessa [141]

Answer:

Step-by-step explanation:

Simplify both sides of the equation.

Subtract 15 from both sides.

Divide both sides by -2.

x = 11

3 0

2 years ago

Power bills usually show _____.

kvasek [131]

Answer:

the amount you owe, and how much energy you have used

7 0

2 years ago

Read 2 more answers

Midpoint question......

ludmilkaskok [199]

I believe it would be 5.1 if this is incorrect then I’m so sorry

4 0

2 years ago

Students were surveyed about their favorite kind of frozen yogurt

Oxana [17]

What do you exactly need help with?

5 0

2 years ago

Solve square root of x + square root of x+2 = 2

andrew-mc [135]

The value of x is $\frac{1}{4}$

Step-by-step explanation:

Given:

$\sqrt{x} + \sqrt{x + 2} = 2$

Rearranging the radical on left side,

$\sqrt{x + 2} = 2 - \sqrt{x}$

Power on both sides,

$(\sqrt{x + 2})^{2} = (2 - \sqrt{x})^{2}$

Simplifying the left,

$x + 2 = (2 - \sqrt{x} )^{2}$

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

$= > x + 2 = {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}$

Now calculating its powers,

$= > x + 2 = 4 - 4\sqrt{x} + x$

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

$= > 4 \sqrt{x} = 4 + x - x - 2$

Now the +x and -x will be cancelled,

$= > 4 \sqrt{x} = 4 - 2$

$= > 4 \sqrt{x} = 2$

Bringing 4 to the right side, it becomes the denominator,

$= > \sqrt{x} = \frac{2}{4}$

$= > \sqrt{x} = \frac{1}{4}$

Now powering both sides,

$= > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}$

$= > x = \frac{1}{4}$

4 0

2 years ago