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Elodia [21]
3 years ago
5

Chan wants to buy a used car that costs $8,500. He took out a loan for the cost of the car, and his payments are $209 per month

for four years. At the end of four years how much more than the cars original price will he have paid?
Mathematics
1 answer:
timama [110]3 years ago
4 0
He would have paid about $1,532 dallors for the car after 4 years than the original price he has to pay for the monthly pay for the car.
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Express the extended fraction at the right as a simple fraction in lowest terms.
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Answer: 5/2

Yes it has to be 5/2

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In Diagram 6, JCK is a tangent to the circle ABC
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Which of the following numbers is not written in scientific notation?
Sonja [21]

Answer A

Step-by-step explanation:

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Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
Can someone plz help me find the area for this composite figure plzzzz I beg u
Anarel [89]

S_1 = \frac{a+b}{2}h = \frac{7+9}{2}*5=\frac{18*5}{2}= 9 * 5 = 45~m^2

S_\triangle = \frac{ab}{2} = \frac{5*9}{2} = \frac{45}{2} = 22,5~m^2

S = S_1 + S_\triangle = 45 + 22,5 = 67,5~m^2

Answer: 67,5 m².

5 0
3 years ago
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