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kow [346]
3 years ago
11

Please help me!!!!!!!

Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

Is A I think

Step-by-step explanation:

I hope this was helpful I did it on my book :)

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The perimeter of a rectangular garage
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46/10 = 4.6 meters


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3 years ago
MAKING BRAINLIEST
SIZIF [17.4K]

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2 years ago
A square-shaped canvas painting was enlarged by adding a 4-centimeter wide decorative frame to the length and width of the canva
MrMuchimi

<u>ANSWER:</u>

The bare canvas is of 17 cm length.

<u>SOLUTION:</u>

Given, a square-shaped canvas painting was enlarged by adding a 4-centimeter wide decorative frame to the length and width of the canvas.  

The area of the framed painting is 625 cm^2,  

Let, the length of the bare paintings be x.

Then, after adding the frame,  

length becomes x + 4 + 4 = x + 8. [we added 4 two times, because frame adds on both sides of painting.]

Now, we are given that, area of the framed painting is 625 cm^2

Area = 625

Length^2 = 625

(x + 8)^2= 25^2

x + 8 = 25

x = 25 – 8  = 17

Hence, the bare canvas is of 17 cm length.

4 0
3 years ago
Read 2 more answers
Can someone help? Solve for x
Luba_88 [7]
The answer is A) x = 9

We know this because every four sided figure has angles that measure up to 360. So we can subtract all of the angles and then use the remaining angle to solve the problem. 

360 - 90 - 90 - 99 = 81. 

So with the remaining angle being 81, we can solve for x. 

x^2 = 81
x = +/-9 

Since +9 is the only answer that makes sense in this case, x = 9. 
8 0
3 years ago
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I need help please thanks​
nikdorinn [45]

Answer:

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5 0
3 years ago
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