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jeka94
3 years ago
11

A square-shaped canvas painting was enlarged by adding a 4-centimeter wide decorative frame to the length and width of the canva

s. If the area of the framed painting is 625 square centimeters, what is the side length of the bare canvas?
Mathematics
2 answers:
stealth61 [152]3 years ago
5 0

Answer:

17 centimeters

Step-by-step explanation:

MrMuchimi3 years ago
4 0

<u>ANSWER:</u>

The bare canvas is of 17 cm length.

<u>SOLUTION:</u>

Given, a square-shaped canvas painting was enlarged by adding a 4-centimeter wide decorative frame to the length and width of the canvas.  

The area of the framed painting is 625 cm^2,  

Let, the length of the bare paintings be x.

Then, after adding the frame,  

length becomes x + 4 + 4 = x + 8. [we added 4 two times, because frame adds on both sides of painting.]

Now, we are given that, area of the framed painting is 625 cm^2

Area = 625

Length^2 = 625

(x + 8)^2= 25^2

x + 8 = 25

x = 25 – 8  = 17

Hence, the bare canvas is of 17 cm length.

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mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

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P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

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Answer:

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Step-by-step explanation:

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