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PilotLPTM [1.2K]
3 years ago
15

Is a 4(2x-3)<8(x+1) always ,sometime,or never true?

Mathematics
2 answers:
Taya2010 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

8

x

−

12

<

8

x

+

8

Step 2: Subtract 8x from both sides.

8

x

−

12

−

8

x

<

8

x

+

8

−

8

x

−

12

<

8

Step 3: Add 12 to both sides.

−

12

+

12

<

8

+

12

0

<

20

yarga [219]3 years ago
3 0

Answer:

true

Step-by-step explanation:

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What is the area of a regular hexagon if a side is 30
sergij07 [2.7K]
<h3>Answer:</h3>

1350\sqrt{3} square units (approximately 2338.26859)

<h3>Step-by-step explanation:</h3>

The formula for finding the area of a regular hexagon when you know its side length is A=\frac{3\sqrt{3}*s^2}{2}, where A is the area and s is the side length.

  1. Substitute in the side length. A=\frac{3\sqrt{3}*30^2}{2}
  2. Simplify the exponent. A=\frac{3\sqrt{3}*900}{2}
  3. Multiply. A=\frac{2700\sqrt{3}}{2}
  4. Divide. A=1350\sqrt{3}

1350\sqrt{3} is as simple as the solution can get without estimating, but you can estimate with a calculator to find that it is approximately 2338.26859.

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Plz help me with this !!
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